(2/x-1)+(9/x)=(-3/x^2-1)

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Solution for (2/x-1)+(9/x)=(-3/x^2-1) equation:



(2/x-1)+(9/x)=(-3/x^2-1)
We move all terms to the left:
(2/x-1)+(9/x)-((-3/x^2-1))=0
Domain of the equation: x-1)!=0
x∈R
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x^2-1))!=0
x∈R
We add all the numbers together, and all the variables
(2/x-1)+(+9/x)-((-3/x^2-1))=0
We get rid of parentheses
2/x+9/x-((-3/x^2-1))-1=0
We calculate fractions
We do not support expression: x^3

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